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10. If f(x) = x2 – 3, where x is an integer, which of the following could be a value of f(x)?

　　I 6

　　II 0

　　III -6

A. I only

　　B. I and II only

　　C. II and III only

　　D. I and III only

　　E. I, II and III

　　Correct Answer: A

Explanation:

Choice I is correct because f(x) = 6 when x=3. Choice II is incorrect because to make f(x) = 0, x2 would have to be 3. But 3 is not the square of an integer. Choice III is incorrect because to make f(x) = 0, x2 would have to be –3 but squares cannot be negative. (The minimum value for x2 is zero; hence, the minimum value for f(x) = -3)

11. For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 200?

　　A. 48

　　B. 49

　　C. 50

　　D. 51

　　E. 52

Correct Answer: C

Explanation:

1 < 4n + 7 < 200. n can be 0, or -1. n cannot be -2 or any other negative integer or the expression 4n + 7 will be less than1. The largest value for n will be an integer < (200 - 7) /4. 193/4 = 48.25, hence 48. The number of integers between -1 and 48 inclusive is 50

12. In the following correctly worked addition sum, A,B,C and D represent different digits, and all the digits in the sum are different. What is the sum of A,B,C and D?

　　A. 23

　　B. 22

　　C. 18

　　D. 16

　　E. 14

Correct Answer: B

Explanation:

First you must realize that the sum of two 2-digit numbers cannot be more that 198 (99 + 99). Therefore in the given problem D must be 1. Now use trial and error to satisfy the sum 5A + BC = 143. A + C must give 3 in the units place, but neither can be 1 since all the digits have to be different. Therefore A + C = 13. With one to carry over into the tens column, 1 + 5 + B = 14, and B = 8. A + C + B + D = 13 + 8 + 1 = 22

延伸阅读：

SAT数学练习题（一）

SAT数学练习题（二）

SAT数学练习题（三）

更多阅读资料：
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